SQL 50, decoded
0 of 50 solved/50

1729. Find Followers Count

SQL 50 · Sorting and Grouping (day 4). Decode it with the hints, solve it on LeetCode, then compare with the reference solution in MySQLPostgreSQL.

EasySolve it on LeetCode ↗

Your work

Hints

Open one at a time. Try to finish with as few as you can.

1. What does one output row represent?
One user.
2. Approach
GROUP BY user_id, COUNT(follower_id), ORDER BY user_id.
3. The trap
Straight GROUP BY; nothing hidden.

Reference solution

Tested on MySQL 8.0 and PostgreSQL 16. Switch dialect at the top of the page.

Show the MySQLPostgreSQL solution
SELECT user_id, COUNT(follower_id) AS followers_count
FROM Followers
GROUP BY user_id
ORDER BY user_id;